M 408C · Flashcards
M 408C Exam Review: Limits, Continuity, Derivatives, Mean Value Theorem and Integration
30 termsThe University of Texas at Austinby @studyboardUpdated October 2026
A study set written by the Studyboard team for the topics in this course's published outline. It isn't official course material from The University of Texas at Austin and doesn't contain real exam questions.
Terms in this set (30)
- When does lim as x→a of f(x) exist?When the left-hand limit and the right-hand limit both exist and are equal. The value of f(a) itself does not matter for the limit.
- Evaluate lim as x→2 of (x^2 − 4)/(x − 2).Factor: (x − 2)(x + 2)/(x − 2) = x + 2 for x ≠ 2, so the limit is 4.
- State the squeeze theorem and give its classic use.If g(x) ≤ f(x) ≤ h(x) near a and lim g = lim h = L, then lim f = L. It shows lim as x→0 of x^2 sin(1/x) = 0, since −x^2 ≤ x^2 sin(1/x) ≤ x^2.
- Two key trigonometric limitslim as x→0 of sin x / x = 1 (x in radians), and lim as x→0 of (1 − cos x)/x = 0.
- Three conditions for f to be continuous at x = af(a) is defined, lim as x→a of f(x) exists, and the limit equals f(a).
- State the Intermediate Value Theorem.If f is continuous on [a, b] and N is between f(a) and f(b), then f(c) = N for some c in (a, b). It is often used to show a root exists when f(a) and f(b) have opposite signs.
- Removable vs jump vs infinite discontinuityRemovable: the limit exists but differs from f(a) or f(a) is undefined (a hole). Jump: the one-sided limits exist but differ. Infinite: f grows without bound near a (vertical asymptote).
- Horizontal asymptotes of rational functionsCompare degrees: if numerator degree < denominator degree, y = 0. If equal, y = ratio of leading coefficients. If numerator degree is larger, there is no horizontal asymptote.
- State the epsilon-delta definition of lim as x→a of f(x) = L.For every ε > 0 there is a δ > 0 such that if 0 < |x − a| < δ, then |f(x) − L| < ε.
- Evaluate lim as h→0 of [(2 + h)^3 − 8]/h without expanding.This is the definition of the derivative of x^3 at x = 2. Since d/dx [x^3] = 3x^2, the limit is 3(2)^2 = 12.
- Equation of the tangent line to y = f(x) at x = ay = f(a) + f'(a)(x − a). Example: for f(x) = x^2 at a = 3, y = 9 + 6(x − 3).
- Differentiate e^(3x^2).By the chain rule: d/dx [e^(3x^2)] = e^(3x^2)·6x.
- Use logarithmic differentiation to find the derivative of y = x^x.ln y = x ln x. Differentiate: y'/y = ln x + 1. So y' = x^x(ln x + 1).
- Derivatives of ln|x| and log_b(x)d/dx [ln|x|] = 1/x for x ≠ 0. d/dx [log_b x] = 1/(x ln b).
- Derivatives of arcsin x and arctan xd/dx [arcsin x] = 1/sqrt(1 − x^2) for |x| < 1. d/dx [arctan x] = 1/(1 + x^2).
- State Rolle's Theorem.If f is continuous on [a, b], differentiable on (a, b), and f(a) = f(b), then f'(c) = 0 for some c in (a, b).
- State the Mean Value Theorem.If f is continuous on [a, b] and differentiable on (a, b), then for some c in (a, b), f'(c) = [f(b) − f(a)]/(b − a): the tangent slope equals the average slope somewhere.
- What important consequence follows from the Mean Value Theorem about f' = 0?If f'(x) = 0 for all x in an interval, then f is constant there. So two functions with the same derivative on an interval differ by a constant.
- When can you use L'Hôpital's rule?Only for indeterminate forms 0/0 or ∞/∞. Other forms like 0·∞, ∞ − ∞, 1^∞, 0^0 or ∞^0 must first be rewritten as a quotient (often using logarithms).
- Evaluate lim as x→∞ of (ln x)/x.It is ∞/∞, so apply L'Hôpital: lim (1/x)/1 = 0. Polynomials grow faster than logarithms.
- Basic antiderivatives: x^n and 1/x∫ x^n dx = x^(n+1)/(n + 1) + C for n ≠ −1. ∫ (1/x) dx = ln|x| + C. Do not forget the constant of integration.
- Definite integral as a limit of Riemann sumsThe integral from a to b of f(x) dx = lim as n→∞ of the sum from i = 1 to n of f(x_i*)·Δx, where Δx = (b − a)/n and x_i* is a sample point in the i-th subinterval.
- Fundamental Theorem of Calculus, Part 1 (with chain rule)If F(x) = integral from a to x of f(t) dt with f continuous, then F'(x) = f(x). If the upper limit is g(x), the derivative is f(g(x))·g'(x).
- Fundamental Theorem of Calculus, Part 2If F is any antiderivative of a continuous f on [a, b], then the integral from a to b of f(x) dx = F(b) − F(a).
- Evaluate the integral of sin x from 0 to π.An antiderivative is −cos x, so the integral = −cos π − (−cos 0) = 1 + 1 = 2.
- Use u-substitution: ∫ 2x cos(x^2) dxLet u = x^2, so du = 2x dx. The integral becomes ∫ cos u du = sin u + C = sin(x^2) + C.
- How do you find the area between two curves?Area = integral from a to b of [top function − bottom function] dx, where a and b are usually the intersection points. If the curves cross, split the interval.
- Properties: reversing limits and splitting the interval of a definite integralThe integral from b to a of f = −(the integral from a to b of f). The integral from a to c of f = (integral from a to b) + (integral from b to c).
- Integrals of odd and even functions over [−a, a]If f is odd (f(−x) = −f(x)), the integral from −a to a is 0. If f is even (f(−x) = f(x)), it equals 2 × the integral from 0 to a.
- What is a differential, and how does it estimate change?dy = f'(x)·dx. For a small change dx in x, the actual change Δy is approximately dy, which is the change along the tangent line.
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